123131310000001 has 4 divisors (see below), whose sum is σ = 125751125106432. Its totient is φ = 120511494893572.

The previous prime is 123131309999977. The next prime is 123131310000043. The reversal of 123131310000001 is 100000013131321.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 123131310000001 - 2¹⁵ = 123131309967233 is a prime.

It is a super-2 number, since 2×123131310000001² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 123131310000001.

It is not an unprimeable number, because it can be changed into a prime (123131310000091) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1309907553145 + ... + 1309907553238.

It is an arithmetic number, because the mean of its divisors is an integer number (31437781276608).

Almost surely, 2^{123131310000001} is an apocalyptic number.

It is an amenable number.

123131310000001 is a deficient number, since it is larger than the sum of its proper divisors (2619815106431).

123131310000001 is an equidigital number, since it uses as much as digits as its factorization.

123131310000001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2619815106430.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 123131310000001 its reverse (100000013131321), we get a palindrome (223131323131322).

The spelling of 123131310000001 in words is "one hundred twenty-three trillion, one hundred thirty-one billion, three hundred ten million, one", and thus it is an aban number.