Base | Representation |
---|---|
bin | 11011111111110010111101… |
… | …111111100100011110101011 |
3 | 121010222020102200222110020111 |
4 | 123333302331333210132223 |
5 | 112114340410330000133 |
6 | 1113513424245235151 |
7 | 34635641435055562 |
oct | 3377627577443653 |
9 | 533866380873214 |
10 | 123131310000043 |
11 | 36262771517484 |
12 | 1198780a702ab7 |
13 | 539230435ac47 |
14 | 22598313d6bd9 |
15 | e37ddbc261cd |
hex | 6ffcbdfe47ab |
123131310000043 has 2 divisors, whose sum is σ = 123131310000044. Its totient is φ = 123131310000042.
The previous prime is 123131309999977. The next prime is 123131310000079. The reversal of 123131310000043 is 340000013131321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 123131310000043 - 229 = 123130773129131 is a prime.
It is a super-2 number, since 2×1231313100000432 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 123131309999969 and 123131310000023.
It is not a weakly prime, because it can be changed into another prime (123131310000343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61565655000021 + 61565655000022.
It is an arithmetic number, because the mean of its divisors is an integer number (61565655000022).
Almost surely, 2123131310000043 is an apocalyptic number.
123131310000043 is a deficient number, since it is larger than the sum of its proper divisors (1).
123131310000043 is an equidigital number, since it uses as much as digits as its factorization.
123131310000043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 123131310000043 its reverse (340000013131321), we get a palindrome (463131323131364).
The spelling of 123131310000043 in words is "one hundred twenty-three trillion, one hundred thirty-one billion, three hundred ten million, forty-three", and thus it is an aban number.
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