Base | Representation |
---|---|
bin | 1011001100101110010000… |
… | …0010011001000000111010 |
3 | 1121121010112020002102021112 |
4 | 2303023210002121000322 |
5 | 3103214414214233310 |
6 | 42104335034040322 |
7 | 2410412424654203 |
oct | 263134402310072 |
9 | 47533466072245 |
10 | 12313202102330 |
11 | 3a17aaa644a78 |
12 | 146a46a5790a2 |
13 | 6b418c73235c |
14 | 307d682585aa |
15 | 165464653705 |
hex | b32e409903a |
12313202102330 has 16 divisors (see below), whose sum is σ = 22200277409280. Its totient is φ = 4917166702032.
The previous prime is 12313202102321. The next prime is 12313202102353. The reversal of 12313202102330 is 3320120231321.
It is a super-2 number, since 2×123132021023302 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12313202102296 and 12313202102305.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1014260990 + ... + 1014273129.
It is an arithmetic number, because the mean of its divisors is an integer number (1387517338080).
Almost surely, 212313202102330 is an apocalyptic number.
12313202102330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12313202102330 is a deficient number, since it is larger than the sum of its proper divisors (9887075306950).
12313202102330 is a wasteful number, since it uses less digits than its factorization.
12313202102330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2028534733.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 12313202102330 its reverse (3320120231321), we get a palindrome (15633322333651).
The spelling of 12313202102330 in words is "twelve trillion, three hundred thirteen billion, two hundred two million, one hundred two thousand, three hundred thirty".
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