12313311330013 has 4 divisors (see below), whose sum is σ = 12313667333248. Its totient is φ = 12312955326780.

The previous prime is 12313311329981. The next prime is 12313311330017. The reversal of 12313311330013 is 31003311331321.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12313311330013 - 2⁵ = 12313311329981 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12313311330013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12313311330017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 177949731 + ... + 178018912.

It is an arithmetic number, because the mean of its divisors is an integer number (3078416833312).

Almost surely, 2^{12313311330013} is an apocalyptic number.

It is an amenable number.

12313311330013 is a deficient number, since it is larger than the sum of its proper divisors (356003235).

12313311330013 is an equidigital number, since it uses as much as digits as its factorization.

12313311330013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 356003234.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 12313311330013 its reverse (31003311331321), we get a palindrome (43316622661334).

The spelling of 12313311330013 in words is "twelve trillion, three hundred thirteen billion, three hundred eleven million, three hundred thirty thousand, thirteen".