Base | Representation |
---|---|
bin | 11011111111110101100000… |
… | …011100001010001010110011 |
3 | 121010222111110122022021212011 |
4 | 123333311200130022022303 |
5 | 112114412001030402233 |
6 | 1113514554524143351 |
7 | 34636066120444231 |
oct | 3377654034121263 |
9 | 533874418267764 |
10 | 123134035403443 |
11 | 3626393a984389 |
12 | 1198824b397b57 |
13 | 5392649b9a38c |
14 | 2259a0d35d951 |
15 | e37eeb1280cd |
hex | 6ffd6070a2b3 |
123134035403443 has 2 divisors, whose sum is σ = 123134035403444. Its totient is φ = 123134035403442.
The previous prime is 123134035403437. The next prime is 123134035403453. The reversal of 123134035403443 is 344304530431321.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 123134035403443 - 25 = 123134035403411 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 123134035403396 and 123134035403405.
It is not a weakly prime, because it can be changed into another prime (123134035403413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61567017701721 + 61567017701722.
It is an arithmetic number, because the mean of its divisors is an integer number (61567017701722).
Almost surely, 2123134035403443 is an apocalyptic number.
123134035403443 is a deficient number, since it is larger than the sum of its proper divisors (1).
123134035403443 is an equidigital number, since it uses as much as digits as its factorization.
123134035403443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 622080, while the sum is 40.
Adding to 123134035403443 its reverse (344304530431321), we get a palindrome (467438565834764).
The spelling of 123134035403443 in words is "one hundred twenty-three trillion, one hundred thirty-four billion, thirty-five million, four hundred three thousand, four hundred forty-three".
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