Base | Representation |
---|---|
bin | 10001111010110001100… |
… | …110111001010100011101 |
3 | 11100201022020012220101121 |
4 | 101322301212321110131 |
5 | 130133241121111031 |
6 | 2341400414210541 |
7 | 154650522536122 |
oct | 21726146712435 |
9 | 4321266186347 |
10 | 1231340410141 |
11 | 4352326190a6 |
12 | 17a7854b3a51 |
13 | 8c1655961aa |
14 | 438509b2749 |
15 | 2206b338011 |
hex | 11eb19b951d |
1231340410141 has 4 divisors (see below), whose sum is σ = 1231343100000. Its totient is φ = 1231337720284.
The previous prime is 1231340410099. The next prime is 1231340410243. The reversal of 1231340410141 is 1410140431321.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1231340410141 - 233 = 1222750475549 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1231340411141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 467431 + ... + 1637428.
It is an arithmetic number, because the mean of its divisors is an integer number (307835775000).
Almost surely, 21231340410141 is an apocalyptic number.
It is an amenable number.
1231340410141 is a deficient number, since it is larger than the sum of its proper divisors (2689859).
1231340410141 is an equidigital number, since it uses as much as digits as its factorization.
1231340410141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2689858.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1231340410141 its reverse (1410140431321), we get a palindrome (2641480841462).
The spelling of 1231340410141 in words is "one trillion, two hundred thirty-one billion, three hundred forty million, four hundred ten thousand, one hundred forty-one".
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