Base | Representation |
---|---|
bin | 10001111010110001101… |
… | …110100001100111101001 |
3 | 11100201022100222111222111 |
4 | 101322301232201213221 |
5 | 130133242124111332 |
6 | 2341400525122321 |
7 | 154650545536213 |
oct | 21726156414751 |
9 | 4321270874874 |
10 | 1231342410217 |
11 | 435233764857 |
12 | 17a7860b93a1 |
13 | 8c165b1667a |
14 | 43850d735b3 |
15 | 2206b5d0947 |
hex | 11eb1ba19e9 |
1231342410217 has 2 divisors, whose sum is σ = 1231342410218. Its totient is φ = 1231342410216.
The previous prime is 1231342410209. The next prime is 1231342410223. The reversal of 1231342410217 is 7120142431321.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1133945987161 + 97396423056 = 1064869^2 + 312084^2 .
It is a cyclic number.
It is not a de Polignac number, because 1231342410217 - 23 = 1231342410209 is a prime.
It is not a weakly prime, because it can be changed into another prime (1231342410317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 615671205108 + 615671205109.
It is an arithmetic number, because the mean of its divisors is an integer number (615671205109).
Almost surely, 21231342410217 is an apocalyptic number.
It is an amenable number.
1231342410217 is a deficient number, since it is larger than the sum of its proper divisors (1).
1231342410217 is an equidigital number, since it uses as much as digits as its factorization.
1231342410217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 31.
Adding to 1231342410217 its reverse (7120142431321), we get a palindrome (8351484841538).
The spelling of 1231342410217 in words is "one trillion, two hundred thirty-one billion, three hundred forty-two million, four hundred ten thousand, two hundred seventeen".
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