Base | Representation |
---|---|
bin | 10001111010110110000… |
… | …010000100101011110101 |
3 | 11100201111101220100100020 |
4 | 101322312002010223311 |
5 | 130133414122042240 |
6 | 2341412025235353 |
7 | 154652413523550 |
oct | 21726602045365 |
9 | 4321441810306 |
10 | 1231414643445 |
11 | 435270510738 |
12 | 17a7a6332b59 |
13 | 8c177a8781c |
14 | 4385a7b7697 |
15 | 22072aed0d0 |
hex | 11eb6084af5 |
1231414643445 has 64 divisors (see below), whose sum is σ = 2258813952000. Its totient is φ = 561162491136.
The previous prime is 1231414643423. The next prime is 1231414643453. The reversal of 1231414643445 is 5443464141321.
It is not a de Polignac number, because 1231414643445 - 210 = 1231414642421 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1231414643397 and 1231414643406.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 170340091 + ... + 170347319.
It is an arithmetic number, because the mean of its divisors is an integer number (35293968000).
Almost surely, 21231414643445 is an apocalyptic number.
1231414643445 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1231414643445 is a deficient number, since it is larger than the sum of its proper divisors (1027399308555).
1231414643445 is a wasteful number, since it uses less digits than its factorization.
1231414643445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12122.
The product of its digits is 552960, while the sum is 42.
Adding to 1231414643445 its reverse (5443464141321), we get a palindrome (6674878784766).
The spelling of 1231414643445 in words is "one trillion, two hundred thirty-one billion, four hundred fourteen million, six hundred forty-three thousand, four hundred forty-five".
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