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12314222403331 is a prime number
BaseRepresentation
bin1011001100110010000011…
…0110100001111100000011
31121121020011022222002010111
42303030200312201330003
53103224011413401311
642105024202412151
72410446624246532
oct263144066417403
947536138862114
1012314222403331
113a18483574242
12146a6b4201057
136b42c2c29964
1430802396c319
151654c3ee4d21
hexb3320da1f03

12314222403331 has 2 divisors, whose sum is σ = 12314222403332. Its totient is φ = 12314222403330.

The previous prime is 12314222403313. The next prime is 12314222403341. The reversal of 12314222403331 is 13330422241321.

Together with previous prime (12314222403313) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12314222403331 - 29 = 12314222402819 is a prime.

It is a super-2 number, since 2×123142224033312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12314222403293 and 12314222403302.

It is not a weakly prime, because it can be changed into another prime (12314222403341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6157111201665 + 6157111201666.

It is an arithmetic number, because the mean of its divisors is an integer number (6157111201666).

Almost surely, 212314222403331 is an apocalyptic number.

12314222403331 is a deficient number, since it is larger than the sum of its proper divisors (1).

12314222403331 is an equidigital number, since it uses as much as digits as its factorization.

12314222403331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 12314222403331 its reverse (13330422241321), we get a palindrome (25644644644652).

The spelling of 12314222403331 in words is "twelve trillion, three hundred fourteen billion, two hundred twenty-two million, four hundred three thousand, three hundred thirty-one".