Base | Representation |
---|---|
bin | 1011001100110101011110… |
… | …0101011000110100100001 |
3 | 1121121022112022211011120001 |
4 | 2303031113211120310201 |
5 | 3103232402002001132 |
6 | 42105255244020001 |
7 | 2410511444260324 |
oct | 263152745306441 |
9 | 47538468734501 |
10 | 12315140656417 |
11 | 3a18904933395 |
12 | 146a90b831601 |
13 | 6b440b244591 |
14 | 3080ad8ba7bb |
15 | 165529929ce7 |
hex | b3357958d21 |
12315140656417 has 2 divisors, whose sum is σ = 12315140656418. Its totient is φ = 12315140656416.
The previous prime is 12315140656409. The next prime is 12315140656477. The reversal of 12315140656417 is 71465604151321.
12315140656417 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9519008213521 + 2796132442896 = 3085289^2 + 1672164^2 .
It is a cyclic number.
It is not a de Polignac number, because 12315140656417 - 23 = 12315140656409 is a prime.
It is not a weakly prime, because it can be changed into another prime (12315140656477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6157570328208 + 6157570328209.
It is an arithmetic number, because the mean of its divisors is an integer number (6157570328209).
Almost surely, 212315140656417 is an apocalyptic number.
It is an amenable number.
12315140656417 is a deficient number, since it is larger than the sum of its proper divisors (1).
12315140656417 is an equidigital number, since it uses as much as digits as its factorization.
12315140656417 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 604800, while the sum is 46.
The spelling of 12315140656417 in words is "twelve trillion, three hundred fifteen billion, one hundred forty million, six hundred fifty-six thousand, four hundred seventeen".
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