Base | Representation |
---|---|
bin | 1011001100110110110100… |
… | …0101010011000110011111 |
3 | 1121121100110110111221201101 |
4 | 2303031231011103012133 |
5 | 3103234121320440020 |
6 | 42105355130453531 |
7 | 2410523414124154 |
oct | 263155505230637 |
9 | 47540413457641 |
10 | 12315501343135 |
11 | 3a18a7a497691 |
12 | 146a9b05942a7 |
13 | 6b4467b9ca83 |
14 | 30810576a22b |
15 | 16554b42500a |
hex | b336d15319f |
12315501343135 has 16 divisors (see below), whose sum is σ = 14970320346240. Its totient is φ = 9724666049280.
The previous prime is 12315501343133. The next prime is 12315501343139. The reversal of 12315501343135 is 53134310551321.
It is not a de Polignac number, because 12315501343135 - 21 = 12315501343133 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12315501343094 and 12315501343103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12315501343133) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3567582 + ... + 6112171.
It is an arithmetic number, because the mean of its divisors is an integer number (935645021640).
Almost surely, 212315501343135 is an apocalyptic number.
12315501343135 is a deficient number, since it is larger than the sum of its proper divisors (2654819003105).
12315501343135 is an equidigital number, since it uses as much as digits as its factorization.
12315501343135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9683058.
The product of its (nonzero) digits is 81000, while the sum is 37.
Adding to 12315501343135 its reverse (53134310551321), we get a palindrome (65449811894456).
The spelling of 12315501343135 in words is "twelve trillion, three hundred fifteen billion, five hundred one million, three hundred forty-three thousand, one hundred thirty-five".
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