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12315501343139 is a prime number
BaseRepresentation
bin1011001100110110110100…
…0101010011000110100011
31121121100110110111221201112
42303031231011103012203
53103234121320440024
642105355130453535
72410523414124161
oct263155505230643
947540413457645
1012315501343139
113a18a7a497695
12146a9b05942ab
136b4467b9ca87
1430810576a231
1516554b42500e
hexb336d1531a3

12315501343139 has 2 divisors, whose sum is σ = 12315501343140. Its totient is φ = 12315501343138.

The previous prime is 12315501343133. The next prime is 12315501343147. The reversal of 12315501343139 is 93134310551321.

12315501343139 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12315501343139 - 220 = 12315500294563 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12315501343096 and 12315501343105.

It is not a weakly prime, because it can be changed into another prime (12315501343133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6157750671569 + 6157750671570.

It is an arithmetic number, because the mean of its divisors is an integer number (6157750671570).

Almost surely, 212315501343139 is an apocalyptic number.

12315501343139 is a deficient number, since it is larger than the sum of its proper divisors (1).

12315501343139 is an equidigital number, since it uses as much as digits as its factorization.

12315501343139 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 145800, while the sum is 41.

The spelling of 12315501343139 in words is "twelve trillion, three hundred fifteen billion, five hundred one million, three hundred forty-three thousand, one hundred thirty-nine".