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12317149993 is a prime number
BaseRepresentation
bin10110111100010100…
…01100101100101001
31011210101220001100111
423132022030230221
5200211142244433
65354115134321
7614142022201
oct133612145451
934711801314
1012317149993
11525078a105
122478ba43a1
131213a88745
1484bbb7401
154c151adcd
hex2de28cb29

12317149993 has 2 divisors, whose sum is σ = 12317149994. Its totient is φ = 12317149992.

The previous prime is 12317149967. The next prime is 12317149997. The reversal of 12317149993 is 39994171321.

12317149993 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10071527449 + 2245622544 = 100357^2 + 47388^2 .

It is a cyclic number.

It is not a de Polignac number, because 12317149993 - 225 = 12283595561 is a prime.

It is not a weakly prime, because it can be changed into another prime (12317149997) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6158574996 + 6158574997.

It is an arithmetic number, because the mean of its divisors is an integer number (6158574997).

Almost surely, 212317149993 is an apocalyptic number.

It is an amenable number.

12317149993 is a deficient number, since it is larger than the sum of its proper divisors (1).

12317149993 is an equidigital number, since it uses as much as digits as its factorization.

12317149993 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 367416, while the sum is 49.

The spelling of 12317149993 in words is "twelve billion, three hundred seventeen million, one hundred forty-nine thousand, nine hundred ninety-three".