12320000041 has 2 divisors, whose sum is σ = 12320000042. Its totient is φ = 12320000040.

The previous prime is 12319999997. The next prime is 12320000057. The reversal of 12320000041 is 14000002321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10749542400 + 1570457641 = 103680^2 + 39629^2 .

It is an emirp because it is prime and its reverse (14000002321) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12320000041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12319999976 and 12320000030.

It is not a weakly prime, because it can be changed into another prime (12320001041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6160000020 + 6160000021.

It is an arithmetic number, because the mean of its divisors is an integer number (6160000021).

Almost surely, 2^12320000041 is an apocalyptic number.

It is an amenable number.

12320000041 is a deficient number, since it is larger than the sum of its proper divisors (1).

12320000041 is an equidigital number, since it uses as much as digits as its factorization.

12320000041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 13.

Adding to 12320000041 its reverse (14000002321), we get a palindrome (26320002362).

The spelling of 12320000041 in words is "twelve billion, three hundred twenty million, forty-one", and thus it is an aban number.