Base | Representation |
---|---|
bin | 1011001101001001001011… |
… | …1111011100100010000011 |
3 | 1121121211012010000001011201 |
4 | 2303102102333130202003 |
5 | 3103324221132413103 |
6 | 42111532314322031 |
7 | 2411056540504060 |
oct | 263222277344203 |
9 | 47554163001151 |
10 | 12320432310403 |
11 | 3a2007a934348 |
12 | 146b947a29317 |
13 | 6b4a7263b199 |
14 | 3084525bbc67 |
15 | 16573929251d |
hex | b3492fdc883 |
12320432310403 has 24 divisors (see below), whose sum is σ = 14536057132800. Its totient is φ = 10226433693168.
The previous prime is 12320432310401. The next prime is 12320432310451. The reversal of 12320432310403 is 30401323402321.
It is a happy number.
12320432310403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 12320432310403 - 21 = 12320432310401 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12320432310401) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1468783 + ... + 5176696.
It is an arithmetic number, because the mean of its divisors is an integer number (605669047200).
Almost surely, 212320432310403 is an apocalyptic number.
12320432310403 is a deficient number, since it is larger than the sum of its proper divisors (2215624822397).
12320432310403 is an frugal number, since it uses more digits than its factorization.
12320432310403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6645679 (or 6645612 counting only the distinct ones).
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 12320432310403 its reverse (30401323402321), we get a palindrome (42721755712724).
The spelling of 12320432310403 in words is "twelve trillion, three hundred twenty billion, four hundred thirty-two million, three hundred ten thousand, four hundred three".
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