Base | Representation |
---|---|
bin | 10110111100101101… |
… | …01110001111100001 |
3 | 1011210122001211221211 |
4 | 23132112232033201 |
5 | 200213012324441 |
6 | 5354313350121 |
7 | 614211645043 |
oct | 133626561741 |
9 | 34718054854 |
10 | 12320433121 |
11 | 5252621837 |
12 | 247a108341 |
13 | 1214667c19 |
14 | 84c3cda93 |
15 | 4c1968a81 |
hex | 2de5ae3e1 |
12320433121 has 2 divisors, whose sum is σ = 12320433122. Its totient is φ = 12320433120.
The previous prime is 12320433101. The next prime is 12320433149. The reversal of 12320433121 is 12133402321.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11543138721 + 777294400 = 107439^2 + 27880^2 .
It is a cyclic number.
It is not a de Polignac number, because 12320433121 - 211 = 12320431073 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12320433092 and 12320433101.
It is not a weakly prime, because it can be changed into another prime (12320433101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6160216560 + 6160216561.
It is an arithmetic number, because the mean of its divisors is an integer number (6160216561).
Almost surely, 212320433121 is an apocalyptic number.
It is an amenable number.
12320433121 is a deficient number, since it is larger than the sum of its proper divisors (1).
12320433121 is an equidigital number, since it uses as much as digits as its factorization.
12320433121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 22.
Adding to 12320433121 its reverse (12133402321), we get a palindrome (24453835442).
The spelling of 12320433121 in words is "twelve billion, three hundred twenty million, four hundred thirty-three thousand, one hundred twenty-one".
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