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1232076033457 is a prime number
BaseRepresentation
bin10001111011011101011…
…101000100110110110001
311100210012111102102212121
4101323131131010312301
5130141242431032312
62342001413154241
7155004664326403
oct21733535046661
94323174372777
101232076033457
1143557a889855
1217a94b92b981
138c251ac8c69
14438c0580b73
15220b0be5707
hex11edd744db1

1232076033457 has 2 divisors, whose sum is σ = 1232076033458. Its totient is φ = 1232076033456.

The previous prime is 1232076033449. The next prime is 1232076033493. The reversal of 1232076033457 is 7543306702321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1232064480256 + 11553201 = 1109984^2 + 3399^2 .

It is a cyclic number.

It is not a de Polignac number, because 1232076033457 - 23 = 1232076033449 is a prime.

It is a super-2 number, since 2×12320760334572 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1232076033407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 616038016728 + 616038016729.

It is an arithmetic number, because the mean of its divisors is an integer number (616038016729).

Almost surely, 21232076033457 is an apocalyptic number.

It is an amenable number.

1232076033457 is a deficient number, since it is larger than the sum of its proper divisors (1).

1232076033457 is an equidigital number, since it uses as much as digits as its factorization.

1232076033457 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 635040, while the sum is 43.

The spelling of 1232076033457 in words is "one trillion, two hundred thirty-two billion, seventy-six million, thirty-three thousand, four hundred fifty-seven".