Base | Representation |
---|---|
bin | 11100000000111100010111… |
… | …101000001001100001011011 |
3 | 121011020202212022221220120011 |
4 | 130000330113220021201123 |
5 | 112122133313021033313 |
6 | 1114013541010142351 |
7 | 34644431466305323 |
oct | 3400742750114133 |
9 | 534222768856504 |
10 | 123210123221083 |
11 | 362931355279a8 |
12 | 1199ab44b819b7 |
13 | 539988464a292 |
14 | 225d58a6c4283 |
15 | e39ea0e1b93d |
hex | 700f17a0985b |
123210123221083 has 2 divisors, whose sum is σ = 123210123221084. Its totient is φ = 123210123221082.
The previous prime is 123210123221077. The next prime is 123210123221161. The reversal of 123210123221083 is 380122321012321.
It is a weak prime.
It is an emirp because it is prime and its reverse (380122321012321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 123210123221083 - 229 = 123209586350171 is a prime.
It is not a weakly prime, because it can be changed into another prime (123510123221083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61605061610541 + 61605061610542.
It is an arithmetic number, because the mean of its divisors is an integer number (61605061610542).
Almost surely, 2123210123221083 is an apocalyptic number.
123210123221083 is a deficient number, since it is larger than the sum of its proper divisors (1).
123210123221083 is an equidigital number, since it uses as much as digits as its factorization.
123210123221083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 31.
The spelling of 123210123221083 in words is "one hundred twenty-three trillion, two hundred ten billion, one hundred twenty-three million, two hundred twenty-one thousand, eighty-three".
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