Base | Representation |
---|---|
bin | 11100000000111101100000… |
… | …110100010101110111010110 |
3 | 121011020220000220112101001001 |
4 | 130000331200310111313112 |
5 | 112122143321343413014 |
6 | 1114014302513053514 |
7 | 34644504066463135 |
oct | 3400754064256726 |
9 | 534226026471031 |
10 | 123211351154134 |
11 | 36293705682201 |
12 | 1199b22825729a |
13 | 5399a1bb71999 |
14 | 225d66580591c |
15 | e3a023b23974 |
hex | 700f60d15dd6 |
123211351154134 has 8 divisors (see below), whose sum is σ = 184817073881160. Its totient is φ = 61605659860416.
The previous prime is 123211351154051. The next prime is 123211351154149. The reversal of 123211351154134 is 431451153112321.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-3 number, since 3×1232113511541343 (a number of 43 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 123211351154093 and 123211351154102.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10826982 + ... + 19069510.
It is an arithmetic number, because the mean of its divisors is an integer number (23102134235145).
Almost surely, 2123211351154134 is an apocalyptic number.
123211351154134 is a deficient number, since it is larger than the sum of its proper divisors (61605722727026).
123211351154134 is an equidigital number, since it uses as much as digits as its factorization.
123211351154134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15716654.
The product of its digits is 43200, while the sum is 37.
The spelling of 123211351154134 in words is "one hundred twenty-three trillion, two hundred eleven billion, three hundred fifty-one million, one hundred fifty-four thousand, one hundred thirty-four".
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