Base | Representation |
---|---|
bin | 10110111100110100… |
… | …00100100110011011 |
3 | 1011210200201110100201 |
4 | 23132122010212123 |
5 | 200213223424011 |
6 | 5354344243031 |
7 | 614222262613 |
oct | 133632044633 |
9 | 34720643321 |
10 | 12321311131 |
11 | 5253071468 |
12 | 247a470477 |
13 | 12148b475c |
14 | 84c57ba43 |
15 | 4c1a8dcc1 |
hex | 2de68499b |
12321311131 has 2 divisors, whose sum is σ = 12321311132. Its totient is φ = 12321311130.
The previous prime is 12321311099. The next prime is 12321311141. The reversal of 12321311131 is 13111312321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12321311131 - 25 = 12321311099 is a prime.
It is a super-2 number, since 2×123213111312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12321311099 and 12321311108.
It is not a weakly prime, because it can be changed into another prime (12321311141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6160655565 + 6160655566.
It is an arithmetic number, because the mean of its divisors is an integer number (6160655566).
Almost surely, 212321311131 is an apocalyptic number.
12321311131 is a deficient number, since it is larger than the sum of its proper divisors (1).
12321311131 is an equidigital number, since it uses as much as digits as its factorization.
12321311131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 108, while the sum is 19.
Adding to 12321311131 its reverse (13111312321), we get a palindrome (25432623452).
The spelling of 12321311131 in words is "twelve billion, three hundred twenty-one million, three hundred eleven thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •