Base | Representation |
---|---|
bin | 10001111011100111010… |
… | …100011010011001011001 |
3 | 11100210122000211202200211 |
4 | 101323213110122121121 |
5 | 130142112313101203 |
6 | 2342030044331121 |
7 | 155012044140031 |
oct | 21734724323131 |
9 | 4323560752624 |
10 | 1232241534553 |
11 | 435655249217 |
12 | 17a997243aa1 |
13 | 8c27a1945c3 |
14 | 438d85428c1 |
15 | 220c04d7c6d |
hex | 11ee751a659 |
1232241534553 has 2 divisors, whose sum is σ = 1232241534554. Its totient is φ = 1232241534552.
The previous prime is 1232241534521. The next prime is 1232241534599. The reversal of 1232241534553 is 3554351422321.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1199381996569 + 32859537984 = 1095163^2 + 181272^2 .
It is a cyclic number.
It is not a de Polignac number, because 1232241534553 - 25 = 1232241534521 is a prime.
It is not a weakly prime, because it can be changed into another prime (1232241534353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 616120767276 + 616120767277.
It is an arithmetic number, because the mean of its divisors is an integer number (616120767277).
Almost surely, 21232241534553 is an apocalyptic number.
It is an amenable number.
1232241534553 is a deficient number, since it is larger than the sum of its proper divisors (1).
1232241534553 is an equidigital number, since it uses as much as digits as its factorization.
1232241534553 is an evil number, because the sum of its binary digits is even.
The product of its digits is 432000, while the sum is 40.
Adding to 1232241534553 its reverse (3554351422321), we get a palindrome (4786592956874).
The spelling of 1232241534553 in words is "one trillion, two hundred thirty-two billion, two hundred forty-one million, five hundred thirty-four thousand, five hundred fifty-three".
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