Base | Representation |
---|---|
bin | 1011001101010000100110… |
… | …1101100001010111100011 |
3 | 1121122000022220220110021202 |
4 | 2303110021231201113203 |
5 | 3103342311032202243 |
6 | 42112502105311415 |
7 | 2411160104442551 |
oct | 263241155412743 |
9 | 47560286813252 |
10 | 12322424100323 |
11 | 3a20a02183617 |
12 | 1470202a9556b |
13 | 6b4ccc19c5bc |
14 | 3085a0d3abd1 |
15 | 1658040824b8 |
hex | b3509b615e3 |
12322424100323 has 2 divisors, whose sum is σ = 12322424100324. Its totient is φ = 12322424100322.
The previous prime is 12322424100269. The next prime is 12322424100367. The reversal of 12322424100323 is 32300142422321.
12322424100323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12322424100323 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (12322424100373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6161212050161 + 6161212050162.
It is an arithmetic number, because the mean of its divisors is an integer number (6161212050162).
Almost surely, 212322424100323 is an apocalyptic number.
12322424100323 is a deficient number, since it is larger than the sum of its proper divisors (1).
12322424100323 is an equidigital number, since it uses as much as digits as its factorization.
12322424100323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 12322424100323 its reverse (32300142422321), we get a palindrome (44622566522644).
The spelling of 12322424100323 in words is "twelve trillion, three hundred twenty-two billion, four hundred twenty-four million, one hundred thousand, three hundred twenty-three".
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