Base | Representation |
---|---|
bin | 10001111011101010110… |
… | …111010000100111000001 |
3 | 11100210210011201222112111 |
4 | 101323222313100213001 |
5 | 130142223024014103 |
6 | 2342040011055321 |
7 | 155013365453035 |
oct | 21735267204701 |
9 | 4323704658474 |
10 | 1232301001153 |
11 | 435685875372 |
12 | 17a9b3141541 |
13 | 8c2895b5841 |
14 | 439023c21c5 |
15 | 220c583286d |
hex | 11eeadd09c1 |
1232301001153 has 2 divisors, whose sum is σ = 1232301001154. Its totient is φ = 1232301001152.
The previous prime is 1232301001123. The next prime is 1232301001157. The reversal of 1232301001153 is 3511001032321.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1170276094849 + 62024906304 = 1081793^2 + 249048^2 .
It is an emirp because it is prime and its reverse (3511001032321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1232301001153 - 229 = 1231764130241 is a prime.
It is a super-2 number, since 2×12323010011532 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1232301001157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 616150500576 + 616150500577.
It is an arithmetic number, because the mean of its divisors is an integer number (616150500577).
Almost surely, 21232301001153 is an apocalyptic number.
It is an amenable number.
1232301001153 is a deficient number, since it is larger than the sum of its proper divisors (1).
1232301001153 is an equidigital number, since it uses as much as digits as its factorization.
1232301001153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 540, while the sum is 22.
Adding to 1232301001153 its reverse (3511001032321), we get a palindrome (4743302033474).
The spelling of 1232301001153 in words is "one trillion, two hundred thirty-two billion, three hundred one million, one thousand, one hundred fifty-three".
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