Base | Representation |
---|---|
bin | 11100000001001111111011… |
… | …001001010000101000010011 |
3 | 121011022210001122110212020221 |
4 | 130001033323021100220103 |
5 | 112123004313232320123 |
6 | 1114031332312213511 |
7 | 34646104015543045 |
oct | 3401177311205023 |
9 | 534283048425227 |
10 | 123231120198163 |
11 | 362a102a7a561a |
12 | 119a302499a297 |
13 | 539b84c744183 |
14 | 22605bd16ba95 |
15 | e3a7ce46d25d |
hex | 7013fb250a13 |
123231120198163 has 2 divisors, whose sum is σ = 123231120198164. Its totient is φ = 123231120198162.
The previous prime is 123231120198029. The next prime is 123231120198223. The reversal of 123231120198163 is 361891021132321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 123231120198163 - 213 = 123231120189971 is a prime.
It is not a weakly prime, because it can be changed into another prime (123231120190163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61615560099081 + 61615560099082.
It is an arithmetic number, because the mean of its divisors is an integer number (61615560099082).
Almost surely, 2123231120198163 is an apocalyptic number.
123231120198163 is a deficient number, since it is larger than the sum of its proper divisors (1).
123231120198163 is an equidigital number, since it uses as much as digits as its factorization.
123231120198163 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 93312, while the sum is 43.
The spelling of 123231120198163 in words is "one hundred twenty-three trillion, two hundred thirty-one billion, one hundred twenty million, one hundred ninety-eight thousand, one hundred sixty-three".
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