Base | Representation |
---|---|
bin | 1011001101010111011010… |
… | …0100010011101000100001 |
3 | 1121122012001012102011021011 |
4 | 2303111312210103220201 |
5 | 3103410031100320223 |
6 | 42113403225300521 |
7 | 2411253261651334 |
oct | 263256644235041 |
9 | 47565035364234 |
10 | 12324250401313 |
11 | 3a2175a071584 |
12 | 1470632634741 |
13 | 6b523066aa86 |
14 | 3086d56dc61b |
15 | 1658ae58380d |
hex | b3576913a21 |
12324250401313 has 2 divisors, whose sum is σ = 12324250401314. Its totient is φ = 12324250401312.
The previous prime is 12324250401247. The next prime is 12324250401367. The reversal of 12324250401313 is 31310405242321.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8349921082129 + 3974329319184 = 2889623^2 + 1993572^2 .
It is a cyclic number.
It is not a de Polignac number, because 12324250401313 - 237 = 12186811447841 is a prime.
It is not a weakly prime, because it can be changed into another prime (12324250401383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6162125200656 + 6162125200657.
It is an arithmetic number, because the mean of its divisors is an integer number (6162125200657).
Almost surely, 212324250401313 is an apocalyptic number.
It is an amenable number.
12324250401313 is a deficient number, since it is larger than the sum of its proper divisors (1).
12324250401313 is an equidigital number, since it uses as much as digits as its factorization.
12324250401313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 12324250401313 its reverse (31310405242321), we get a palindrome (43634655643634).
The spelling of 12324250401313 in words is "twelve trillion, three hundred twenty-four billion, two hundred fifty million, four hundred one thousand, three hundred thirteen".
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