Base | Representation |
---|---|
bin | 10110111101001011… |
… | …11100100101000001 |
3 | 1011210220120121102012 |
4 | 23132211330211001 |
5 | 200220023032001 |
6 | 5354535102305 |
7 | 614260606211 |
oct | 133645744501 |
9 | 34726517365 |
10 | 12324424001 |
11 | 52548a818a |
12 | 247b511995 |
13 | 12154345a6 |
14 | 84cb4c241 |
15 | 4c1ea62bb |
hex | 2de97c941 |
12324424001 has 2 divisors, whose sum is σ = 12324424002. Its totient is φ = 12324424000.
The previous prime is 12324423977. The next prime is 12324424033. The reversal of 12324424001 is 10042442321.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11678044225 + 646379776 = 108065^2 + 25424^2 .
It is a cyclic number.
It is not a de Polignac number, because 12324424001 - 210 = 12324422977 is a prime.
It is a super-3 number, since 3×123244240013 (a number of 31 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (12324424051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6162212000 + 6162212001.
It is an arithmetic number, because the mean of its divisors is an integer number (6162212001).
Almost surely, 212324424001 is an apocalyptic number.
It is an amenable number.
12324424001 is a deficient number, since it is larger than the sum of its proper divisors (1).
12324424001 is an equidigital number, since it uses as much as digits as its factorization.
12324424001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 23.
Adding to 12324424001 its reverse (10042442321), we get a palindrome (22366866322).
The spelling of 12324424001 in words is "twelve billion, three hundred twenty-four million, four hundred twenty-four thousand, one".
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