1232514131 has 2 divisors, whose sum is σ = 1232514132. Its totient is φ = 1232514130.

The previous prime is 1232514113. The next prime is 1232514139. The reversal of 1232514131 is 1314152321.

Together with previous prime (1232514113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1232514131 is a prime.

It is a super-2 number, since 2×1232514131² = 3038182166229370322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1232514097 and 1232514106.

It is not a weakly prime, because it can be changed into another prime (1232514139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 616257065 + 616257066.

It is an arithmetic number, because the mean of its divisors is an integer number (616257066).

Almost surely, 2^1232514131 is an apocalyptic number.

1232514131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1232514131 is an equidigital number, since it uses as much as digits as its factorization.

1232514131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 720, while the sum is 23.

The square root of 1232514131 is about 35107.1806187851. The cubic root of 1232514131 is about 1072.1707847170.

Adding to 1232514131 its reverse (1314152321), we get a palindrome (2546666452).

The spelling of 1232514131 in words is "one billion, two hundred thirty-two million, five hundred fourteen thousand, one hundred thirty-one".