Base | Representation |
---|---|
bin | 1011001101011101000100… |
… | …0011011010110001010011 |
3 | 1121122022221222222220000101 |
4 | 2303113101003122301103 |
5 | 3103421133214201301 |
6 | 42114214015433231 |
7 | 2411336014434001 |
oct | 263272103326123 |
9 | 47568858886011 |
10 | 12325768506451 |
11 | 3a22368a98424 |
12 | 1470996b25817 |
13 | 6b541302bb3a |
14 | 3087db195a71 |
15 | 16594c9a7701 |
hex | b35d10dac53 |
12325768506451 has 2 divisors, whose sum is σ = 12325768506452. Its totient is φ = 12325768506450.
The previous prime is 12325768506439. The next prime is 12325768506487. The reversal of 12325768506451 is 15460586752321.
12325768506451 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (15460586752321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12325768506451 - 219 = 12325767982163 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12325768506392 and 12325768506401.
It is not a weakly prime, because it can be changed into another prime (12325768806451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6162884253225 + 6162884253226.
It is an arithmetic number, because the mean of its divisors is an integer number (6162884253226).
Almost surely, 212325768506451 is an apocalyptic number.
12325768506451 is a deficient number, since it is larger than the sum of its proper divisors (1).
12325768506451 is an equidigital number, since it uses as much as digits as its factorization.
12325768506451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096000, while the sum is 55.
The spelling of 12325768506451 in words is "twelve trillion, three hundred twenty-five billion, seven hundred sixty-eight million, five hundred six thousand, four hundred fifty-one".
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