Base | Representation |
---|---|
bin | 1011001101011101001111… |
… | …1001111001100001110011 |
3 | 1121122100002100000012221012 |
4 | 2303113103321321201303 |
5 | 3103421232440431033 |
6 | 42114222445021135 |
7 | 2411340135150056 |
oct | 263272371714163 |
9 | 47570070005835 |
10 | 12325816342643 |
11 | 3a22392aa0471 |
12 | 14709aab547ab |
13 | 6b541cc0a38b |
14 | 308803688a9d |
15 | 165951ca6248 |
hex | b35d3e79873 |
12325816342643 has 2 divisors, whose sum is σ = 12325816342644. Its totient is φ = 12325816342642.
The previous prime is 12325816342597. The next prime is 12325816342657. The reversal of 12325816342643 is 34624361852321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12325816342643 - 226 = 12325749233779 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12325816342591 and 12325816342600.
It is not a weakly prime, because it can be changed into another prime (12325816342243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6162908171321 + 6162908171322.
It is an arithmetic number, because the mean of its divisors is an integer number (6162908171322).
Almost surely, 212325816342643 is an apocalyptic number.
12325816342643 is a deficient number, since it is larger than the sum of its proper divisors (1).
12325816342643 is an equidigital number, since it uses as much as digits as its factorization.
12325816342643 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4976640, while the sum is 50.
The spelling of 12325816342643 in words is "twelve trillion, three hundred twenty-five billion, eight hundred sixteen million, three hundred forty-two thousand, six hundred forty-three".
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