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123299239481497 is a prime number
BaseRepresentation
bin11100000010001111010111…
…010111101101000010011001
3121011120021212222220222212201
4130002033113113231002121
5112130113320301401442
61114122515541010201
734654035045105532
oct3402172727550231
9534507788828781
10123299239481497
1136317a063123a2
12119b42759b3961
1353a50b734a111
142263a02099689
15e3c4698ce7b7
hex7023d75ed099

123299239481497 has 2 divisors, whose sum is σ = 123299239481498. Its totient is φ = 123299239481496.

The previous prime is 123299239481477. The next prime is 123299239481507. The reversal of 123299239481497 is 794184932992321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 120280440955536 + 3018798525961 = 10967244^2 + 1737469^2 .

It is a cyclic number.

It is not a de Polignac number, because 123299239481497 - 227 = 123299105263769 is a prime.

It is a super-2 number, since 2×1232992394814972 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (123299239481477) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61649619740748 + 61649619740749.

It is an arithmetic number, because the mean of its divisors is an integer number (61649619740749).

Almost surely, 2123299239481497 is an apocalyptic number.

It is an amenable number.

123299239481497 is a deficient number, since it is larger than the sum of its proper divisors (1).

123299239481497 is an equidigital number, since it uses as much as digits as its factorization.

123299239481497 is an evil number, because the sum of its binary digits is even.

The product of its digits is 423263232, while the sum is 73.

The spelling of 123299239481497 in words is "one hundred twenty-three trillion, two hundred ninety-nine billion, two hundred thirty-nine million, four hundred eighty-one thousand, four hundred ninety-seven".