Base | Representation |
---|---|
bin | 10001111100010101001… |
… | …011110001000101011001 |
3 | 11100212121122202200110022 |
4 | 101330111023301011121 |
5 | 130200201310120441 |
6 | 2342234253200225 |
7 | 155040106513136 |
oct | 21742513610531 |
9 | 4325548680408 |
10 | 1233011020121 |
11 | 435a0a638101 |
12 | 17ab70a90075 |
13 | 8c3707222ca |
14 | 4396c80758d |
15 | 22117d3384b |
hex | 11f152f1159 |
1233011020121 has 2 divisors, whose sum is σ = 1233011020122. Its totient is φ = 1233011020120.
The previous prime is 1233011020103. The next prime is 1233011020133. The reversal of 1233011020121 is 1210201103321.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1097174546521 + 135836473600 = 1047461^2 + 368560^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1233011020121 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1233011020121.
It is not a weakly prime, because it can be changed into another prime (1233011020421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 616505510060 + 616505510061.
It is an arithmetic number, because the mean of its divisors is an integer number (616505510061).
Almost surely, 21233011020121 is an apocalyptic number.
It is an amenable number.
1233011020121 is a deficient number, since it is larger than the sum of its proper divisors (1).
1233011020121 is an equidigital number, since it uses as much as digits as its factorization.
1233011020121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 1233011020121 its reverse (1210201103321), we get a palindrome (2443212123442).
The spelling of 1233011020121 in words is "one trillion, two hundred thirty-three billion, eleven million, twenty thousand, one hundred twenty-one".
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