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123303525313417 is a prime number
BaseRepresentation
bin11100000010010011010110…
…110100110110101110001001
3121011120200221200110211000021
4130002103112310312232021
5112130201104440012132
61114124505121140441
734654246206062401
oct3402232664665611
9534520850424007
10123303525313417
1136319805583349
12119b507118a721
1353a561b248837
142263ccb375801
15e3c61acb5997
hex7024d6d36b89

123303525313417 has 2 divisors, whose sum is σ = 123303525313418. Its totient is φ = 123303525313416.

The previous prime is 123303525313337. The next prime is 123303525313439. The reversal of 123303525313417 is 714313525303321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 123196258583161 + 107266730256 = 11099381^2 + 327516^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-123303525313417 is a prime.

It is not a weakly prime, because it can be changed into another prime (123303525310417) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61651762656708 + 61651762656709.

It is an arithmetic number, because the mean of its divisors is an integer number (61651762656709).

Almost surely, 2123303525313417 is an apocalyptic number.

It is an amenable number.

123303525313417 is a deficient number, since it is larger than the sum of its proper divisors (1).

123303525313417 is an equidigital number, since it uses as much as digits as its factorization.

123303525313417 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 680400, while the sum is 43.

The spelling of 123303525313417 in words is "one hundred twenty-three trillion, three hundred three billion, five hundred twenty-five million, three hundred thirteen thousand, four hundred seventeen".