Base | Representation |
---|---|
bin | 111001011010111101… |
… | …0111110110101100001 |
3 | 102210021202211010022111 |
4 | 1302311322332311201 |
5 | 4010020133101423 |
6 | 132352015235321 |
7 | 11623524044122 |
oct | 1626572766541 |
9 | 383252733274 |
10 | 123311222113 |
11 | 48328a74322 |
12 | 1ba94818b41 |
13 | b8221c85b1 |
14 | 5d7b004049 |
15 | 331aa2360d |
hex | 1cb5ebed61 |
123311222113 has 2 divisors, whose sum is σ = 123311222114. Its totient is φ = 123311222112.
The previous prime is 123311222039. The next prime is 123311222119. The reversal of 123311222113 is 311222113321.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 62436516129 + 60874705984 = 249873^2 + 246728^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-123311222113 is a prime.
It is not a weakly prime, because it can be changed into another prime (123311222119) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61655611056 + 61655611057.
It is an arithmetic number, because the mean of its divisors is an integer number (61655611057).
Almost surely, 2123311222113 is an apocalyptic number.
It is an amenable number.
123311222113 is a deficient number, since it is larger than the sum of its proper divisors (1).
123311222113 is an equidigital number, since it uses as much as digits as its factorization.
123311222113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 432, while the sum is 22.
Adding to 123311222113 its reverse (311222113321), we get a palindrome (434533335434).
The spelling of 123311222113 in words is "one hundred twenty-three billion, three hundred eleven million, two hundred twenty-two thousand, one hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •