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1233122113 is a prime number
BaseRepresentation
bin100100101111111…
…1111001101000001
310011221100002112101
41021133333031001
510011134401423
6322210030401
742362236126
oct11137771501
93157302471
101233122113
11583079993
122a4b78401
13168620572
14b9ab274d
15733ce7ad
hex497ff341

1233122113 has 2 divisors, whose sum is σ = 1233122114. Its totient is φ = 1233122112.

The previous prime is 1233122089. The next prime is 1233122131. The reversal of 1233122113 is 3112213321.

Together with next prime (1233122131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 643992129 + 589129984 = 25377^2 + 24272^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1233122113 is a prime.

It is not a weakly prime, because it can be changed into another prime (1233122213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 616561056 + 616561057.

It is an arithmetic number, because the mean of its divisors is an integer number (616561057).

Almost surely, 21233122113 is an apocalyptic number.

It is an amenable number.

1233122113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1233122113 is an equidigital number, since it uses as much as digits as its factorization.

1233122113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 216, while the sum is 19.

The square root of 1233122113 is about 35115.8384920537. The cubic root of 1233122113 is about 1072.3470513594.

Adding to 1233122113 its reverse (3112213321), we get a palindrome (4345335434).

It can be divided in two parts, 1233122 and 113, that added together give a triangular number (1233235 = T1570).

The spelling of 1233122113 in words is "one billion, two hundred thirty-three million, one hundred twenty-two thousand, one hundred thirteen".