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123313305511340 = 22572599210066617
BaseRepresentation
bin11100000010011100011101…
…110001010110010110101100
3121011121122012021122100100222
4130002130131301112112230
5112130331122202330330
61114133203412510512
734655043444304100
oct3402343561262654
9534548167570328
10123313305511340
113632297420a84a
12119b6b4061b438
1353a65195376b9
14226457823d900
15e3c9de7070e5
hex70271dc565ac

123313305511340 has 72 divisors (see below), whose sum is σ = 301739690095200. Its totient is φ = 42208265019648.

The previous prime is 123313305511321. The next prime is 123313305511397. The reversal of 123313305511340 is 43115503313321.

It is a super-2 number, since 2×1233133055113402 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (35).

It is a self number, because there is not a number n which added to its sum of digits gives 123313305511340.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 104446289 + ... + 105620328.

It is an arithmetic number, because the mean of its divisors is an integer number (4190829029100).

Almost surely, 2123313305511340 is an apocalyptic number.

123313305511340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

123313305511340 is an abundant number, since it is smaller than the sum of its proper divisors (178426384583860).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

123313305511340 is a wasteful number, since it uses less digits than its factorization.

123313305511340 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 210067239 (or 210067230 counting only the distinct ones).

The product of its (nonzero) digits is 48600, while the sum is 35.

Adding to 123313305511340 its reverse (43115503313321), we get a palindrome (166428808824661).

The spelling of 123313305511340 in words is "one hundred twenty-three trillion, three hundred thirteen billion, three hundred five million, five hundred eleven thousand, three hundred forty".

Divisors: 1 2 4 5 7 10 14 20 28 35 49 70 98 140 196 245 490 599 980 1198 2396 2995 4193 5990 8386 11980 16772 20965 29351 41930 58702 83860 117404 146755 293510 587020 210066617 420133234 840266468 1050333085 1470466319 2100666170 2940932638 4201332340 5881865276 7352331595 10293264233 14704663190 20586528466 29409326380 41173056932 51466321165 102932642330 125829903583 205865284660 251659807166 503319614332 629149517915 880809325081 1258299035830 1761618650162 2516598071660 3523237300324 4404046625405 6165665275567 8808093250810 12331330551134 17616186501620 24662661102268 30828326377835 61656652755670 123313305511340