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123313310253441 = 32711533357382729
BaseRepresentation
bin11100000010011100011110…
…000011011100000110000001
3121011121122012121120021022100
4130002130132003130012001
5112130331124411102231
61114133204102301013
734655043532514340
oct3402343603340601
9534548177507270
10123313310253441
1136322976959640
12119b6b42127769
1353a651a507c89
142264578b15b57
15e3c9ded421e6
hex70271e0dc181

123313310253441 has 48 divisors (see below), whose sum is σ = 226260736940160. Its totient is φ = 62850204668160.

The previous prime is 123313310253383. The next prime is 123313310253457. The reversal of 123313310253441 is 144352013313321.

123313310253441 is a `hidden beast` number, since 1 + 2 + 3 + 3 + 13 + 3 + 102 + 534 + 4 + 1 = 666.

It is not a de Polignac number, because 123313310253441 - 27 = 123313310253313 is a prime.

It is a super-2 number, since 2×1233133102534412 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 123313310253396 and 123313310253405.

It is not an unprimeable number, because it can be changed into a prime (123313310253461) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1678654636 + ... + 1678728093.

It is an arithmetic number, because the mean of its divisors is an integer number (4713765352920).

Almost surely, 2123313310253441 is an apocalyptic number.

123313310253441 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

123313310253441 is a deficient number, since it is larger than the sum of its proper divisors (102947426686719).

123313310253441 is a wasteful number, since it uses less digits than its factorization.

123313310253441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3357382806 (or 3357382803 counting only the distinct ones).

The product of its (nonzero) digits is 77760, while the sum is 36.

Adding to 123313310253441 its reverse (144352013313321), we get a palindrome (267665323566762).

The spelling of 123313310253441 in words is "one hundred twenty-three trillion, three hundred thirteen billion, three hundred ten million, two hundred fifty-three thousand, four hundred forty-one".

Divisors: 1 3 7 9 11 21 33 53 63 77 99 159 231 371 477 583 693 1113 1749 3339 4081 5247 12243 36729 3357382729 10072148187 23501679103 30216444561 36931210019 70505037309 110793630057 177941284637 211515111927 258518470133 332380890171 533823853911 775555410399 1245588992459 1601471561733 1957354131007 2326666231197 3736766977377 5872062393021 11210300932131 13701478917049 17616187179063 41104436751147 123313310253441