Base | Representation |
---|---|
bin | 11100000010011100011110… |
… | …000011011100000110000001 |
3 | 121011121122012121120021022100 |
4 | 130002130132003130012001 |
5 | 112130331124411102231 |
6 | 1114133204102301013 |
7 | 34655043532514340 |
oct | 3402343603340601 |
9 | 534548177507270 |
10 | 123313310253441 |
11 | 36322976959640 |
12 | 119b6b42127769 |
13 | 53a651a507c89 |
14 | 2264578b15b57 |
15 | e3c9ded421e6 |
hex | 70271e0dc181 |
123313310253441 has 48 divisors (see below), whose sum is σ = 226260736940160. Its totient is φ = 62850204668160.
The previous prime is 123313310253383. The next prime is 123313310253457. The reversal of 123313310253441 is 144352013313321.
123313310253441 is a `hidden beast` number, since 1 + 2 + 3 + 3 + 13 + 3 + 102 + 534 + 4 + 1 = 666.
It is not a de Polignac number, because 123313310253441 - 27 = 123313310253313 is a prime.
It is a super-2 number, since 2×1233133102534412 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 123313310253396 and 123313310253405.
It is not an unprimeable number, because it can be changed into a prime (123313310253461) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1678654636 + ... + 1678728093.
It is an arithmetic number, because the mean of its divisors is an integer number (4713765352920).
Almost surely, 2123313310253441 is an apocalyptic number.
123313310253441 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
123313310253441 is a deficient number, since it is larger than the sum of its proper divisors (102947426686719).
123313310253441 is a wasteful number, since it uses less digits than its factorization.
123313310253441 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3357382806 (or 3357382803 counting only the distinct ones).
The product of its (nonzero) digits is 77760, while the sum is 36.
Adding to 123313310253441 its reverse (144352013313321), we get a palindrome (267665323566762).
The spelling of 123313310253441 in words is "one hundred twenty-three trillion, three hundred thirteen billion, three hundred ten million, two hundred fifty-three thousand, four hundred forty-one".
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