123313411204141 has 4 divisors (see below), whose sum is σ = 124026205488732. Its totient is φ = 122600616919552.

The previous prime is 123313411204117. The next prime is 123313411204157. The reversal of 123313411204141 is 141402114313321.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 109308070502500 + 14005340701641 = 10455050^2 + 3742371^2 .

It is a cyclic number.

It is not a de Polignac number, because 123313411204141 - 2¹⁵ = 123313411171373 is a prime.

It is a super-2 number, since 2×123313411204141² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (123313411504141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 356397142036 + ... + 356397142381.

It is an arithmetic number, because the mean of its divisors is an integer number (31006551372183).

Almost surely, 2^{123313411204141} is an apocalyptic number.

It is an amenable number.

123313411204141 is a deficient number, since it is larger than the sum of its proper divisors (712794284591).

123313411204141 is an equidigital number, since it uses as much as digits as its factorization.

123313411204141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 712794284590.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 123313411204141 its reverse (141402114313321), we get a palindrome (264715525517462).

The spelling of 123313411204141 in words is "one hundred twenty-three trillion, three hundred thirteen billion, four hundred eleven million, two hundred four thousand, one hundred forty-one".