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123313411204117 is a prime number
BaseRepresentation
bin11100000010011100100100…
…000100100010010000010101
3121011121122110122112002121021
4130002130210010202100111
5112130331331232012432
61114133222110121141
734655046166546231
oct3402344404422025
9534548418462537
10123313411204117
1136322a1893a352
12119b6b6bab01b1
1353a65353c23c4
1422645882b35c1
15e3c9e8b33697
hex702724122415

123313411204117 has 2 divisors, whose sum is σ = 123313411204118. Its totient is φ = 123313411204116.

The previous prime is 123313411204091. The next prime is 123313411204157. The reversal of 123313411204117 is 711402114313321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 105105021301476 + 18208389902641 = 10252074^2 + 4267129^2 .

It is a cyclic number.

It is not a de Polignac number, because 123313411204117 - 223 = 123313402815509 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (123313411204157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61656705602058 + 61656705602059.

It is an arithmetic number, because the mean of its divisors is an integer number (61656705602059).

Almost surely, 2123313411204117 is an apocalyptic number.

It is an amenable number.

123313411204117 is a deficient number, since it is larger than the sum of its proper divisors (1).

123313411204117 is an equidigital number, since it uses as much as digits as its factorization.

123313411204117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12096, while the sum is 34.

Adding to 123313411204117 its reverse (711402114313321), we get a palindrome (834715525517438).

The spelling of 123313411204117 in words is "one hundred twenty-three trillion, three hundred thirteen billion, four hundred eleven million, two hundred four thousand, one hundred seventeen".