Base | Representation |
---|---|
bin | 11100000010011101001101… |
… | …001000101000000011111111 |
3 | 121011121201020122212210011120 |
4 | 130002131031020220003333 |
5 | 112130334234114023320 |
6 | 1114133414320322023 |
7 | 34655102233456404 |
oct | 3402351510500377 |
9 | 534551218783146 |
10 | 123314100142335 |
11 | 36323241813883 |
12 | 119b7122773313 |
13 | 53a661505a85b |
14 | 22646119ac2ab |
15 | e3ca3936d440 |
hex | 70274d2280ff |
123314100142335 has 32 divisors (see below), whose sum is σ = 207829255008000. Its totient is φ = 62263366799616.
The previous prime is 123314100142327. The next prime is 123314100142361. The reversal of 123314100142335 is 533241001413321.
It is not a de Polignac number, because 123314100142335 - 23 = 123314100142327 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 123314100142296 and 123314100142305.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 147864190 + ... + 148695819.
It is an arithmetic number, because the mean of its divisors is an integer number (6494664219000).
Almost surely, 2123314100142335 is an apocalyptic number.
123314100142335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
123314100142335 is a deficient number, since it is larger than the sum of its proper divisors (84515154865665).
123314100142335 is a wasteful number, since it uses less digits than its factorization.
123314100142335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 296561495.
The product of its (nonzero) digits is 25920, while the sum is 33.
Adding to 123314100142335 its reverse (533241001413321), we get a palindrome (656555101555656).
The spelling of 123314100142335 in words is "one hundred twenty-three trillion, three hundred fourteen billion, one hundred million, one hundred forty-two thousand, three hundred thirty-five".
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