12331414303 has 4 divisors (see below), whose sum is σ = 13279984648. Its totient is φ = 11382843960.

The previous prime is 12331414301. The next prime is 12331414339. The reversal of 12331414303 is 30341413321.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12331414303 - 2¹ = 12331414301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12331414301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 474285153 + ... + 474285178.

It is an arithmetic number, because the mean of its divisors is an integer number (3319996162).

Almost surely, 2^12331414303 is an apocalyptic number.

12331414303 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

12331414303 is a deficient number, since it is larger than the sum of its proper divisors (948570345).

12331414303 is an equidigital number, since it uses as much as digits as its factorization.

12331414303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 948570344.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 12331414303 its reverse (30341413321), we get a palindrome (42672827624).

The spelling of 12331414303 in words is "twelve billion, three hundred thirty-one million, four hundred fourteen thousand, three hundred three".