123314254111045 has 4 divisors (see below), whose sum is σ = 147977104933260. Its totient is φ = 98651403288832.

The previous prime is 123314254111033. The next prime is 123314254111057. The reversal of 123314254111045 is 540111452413321.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (123314254111033) and next prime (123314254111057).

It can be written as a sum of positive squares in 2 ways, for example, as 17394630051969 + 105919624059076 = 4170687^2 + 10291726^2 .

It is a cyclic number.

It is not a de Polignac number, because 123314254111045 - 2³¹ = 123312106627397 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 123314254110995 and 123314254111013.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12331425411100 + ... + 12331425411109.

It is an arithmetic number, because the mean of its divisors is an integer number (36994276233315).

Almost surely, 2^{123314254111045} is an apocalyptic number.

It is an amenable number.

123314254111045 is a deficient number, since it is larger than the sum of its proper divisors (24662850822215).

123314254111045 is an equidigital number, since it uses as much as digits as its factorization.

123314254111045 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24662850822214.

The product of its (nonzero) digits is 57600, while the sum is 37.

The spelling of 123314254111045 in words is "one hundred twenty-three trillion, three hundred fourteen billion, two hundred fifty-four million, one hundred eleven thousand, forty-five".