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12331441343434 = 26165720671717
BaseRepresentation
bin1011001101110010001100…
…1011100100101111001010
31121122212121100102212101211
42303130203023210233022
53104014242440442214
642120552544203334
72411626416651223
oct263344313445712
947585540385354
1012331441343434
113a2480a181854
121471aba90954a
136b5b083a9205
14308bb876024a
15165b80a180c4
hexb37232e4bca

12331441343434 has 4 divisors (see below), whose sum is σ = 18497162015154. Its totient is φ = 6165720671716.

The previous prime is 12331441343393. The next prime is 12331441343437. The reversal of 12331441343434 is 43434314413321.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 10180534583025 + 2150906760409 = 3190695^2 + 1466597^2 .

It is not an unprimeable number, because it can be changed into a prime (12331441343437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3082860335857 + ... + 3082860335860.

Almost surely, 212331441343434 is an apocalyptic number.

12331441343434 is a deficient number, since it is larger than the sum of its proper divisors (6165720671720).

12331441343434 is an equidigital number, since it uses as much as digits as its factorization.

12331441343434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6165720671719.

The product of its digits is 497664, while the sum is 40.

Adding to 12331441343434 its reverse (43434314413321), we get a palindrome (55765755756755).

The spelling of 12331441343434 in words is "twelve trillion, three hundred thirty-one billion, four hundred forty-one million, three hundred forty-three thousand, four hundred thirty-four".

Divisors: 1 2 6165720671717 12331441343434