Search a number
-
+
12331441343437 is a prime number
BaseRepresentation
bin1011001101110010001100…
…1011100100101111001101
31121122212121100102212101221
42303130203023210233031
53104014242440442222
642120552544203341
72411626416651226
oct263344313445715
947585540385357
1012331441343437
113a2480a181857
121471aba909551
136b5b083a9208
14308bb876024d
15165b80a180c7
hexb37232e4bcd

12331441343437 has 2 divisors, whose sum is σ = 12331441343438. Its totient is φ = 12331441343436.

The previous prime is 12331441343393. The next prime is 12331441343449. The reversal of 12331441343437 is 73434314413321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12175116789796 + 156324553641 = 3489286^2 + 395379^2 .

It is a cyclic number.

It is not a de Polignac number, because 12331441343437 - 211 = 12331441341389 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12331441343393 and 12331441343402.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12331441323437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6165720671718 + 6165720671719.

It is an arithmetic number, because the mean of its divisors is an integer number (6165720671719).

Almost surely, 212331441343437 is an apocalyptic number.

It is an amenable number.

12331441343437 is a deficient number, since it is larger than the sum of its proper divisors (1).

12331441343437 is an equidigital number, since it uses as much as digits as its factorization.

12331441343437 is an evil number, because the sum of its binary digits is even.

The product of its digits is 870912, while the sum is 43.

Adding to 12331441343437 its reverse (73434314413321), we get a palindrome (85765755756758).

The spelling of 12331441343437 in words is "twelve trillion, three hundred thirty-one billion, four hundred forty-one million, three hundred forty-three thousand, four hundred thirty-seven".