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123315332031193 is a prime number
BaseRepresentation
bin11100000010011110010110…
…100011111010001011011001
3121011121211102111220012222211
4130002132112203322023121
5112130344244444444233
61114134140444115121
734655144612401201
oct3402362643721331
9534554374805884
10123315332031193
1136323814120145
12119b7407235aa1
1353a6780338983
1422646cb43d401
15e3caac5a75cd
hex7027968fa2d9

123315332031193 has 2 divisors, whose sum is σ = 123315332031194. Its totient is φ = 123315332031192.

The previous prime is 123315332031077. The next prime is 123315332031253. The reversal of 123315332031193 is 391130233513321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 63392297477184 + 59923034554009 = 7961928^2 + 7740997^2 .

It is a cyclic number.

It is not a de Polignac number, because 123315332031193 - 217 = 123315331900121 is a prime.

It is a super-2 number, since 2×1233153320311932 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (123315332031293) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61657666015596 + 61657666015597.

It is an arithmetic number, because the mean of its divisors is an integer number (61657666015597).

Almost surely, 2123315332031193 is an apocalyptic number.

It is an amenable number.

123315332031193 is a deficient number, since it is larger than the sum of its proper divisors (1).

123315332031193 is an equidigital number, since it uses as much as digits as its factorization.

123315332031193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 131220, while the sum is 40.

The spelling of 123315332031193 in words is "one hundred twenty-three trillion, three hundred fifteen billion, three hundred thirty-two million, thirty-one thousand, one hundred ninety-three".