Base | Representation |
---|---|
bin | 11100000010100010101101… |
… | …100000100101011101001011 |
3 | 121011122021111200002102121102 |
4 | 130002202231200211131023 |
5 | 112130433341033100042 |
6 | 1114140233104132015 |
7 | 34655401600452251 |
oct | 3402425540453513 |
9 | 534567450072542 |
10 | 123320012003147 |
11 | 363257a5914363 |
12 | 119b82b260700b |
13 | 53a7047aa664b |
14 | 2264a12bd65d1 |
15 | e3cc83395b32 |
hex | 7028ad82574b |
123320012003147 has 2 divisors, whose sum is σ = 123320012003148. Its totient is φ = 123320012003146.
The previous prime is 123320012003101. The next prime is 123320012003191. The reversal of 123320012003147 is 741300210023321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 123320012003147 - 214 = 123320011986763 is a prime.
It is not a weakly prime, because it can be changed into another prime (123320012003347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61660006001573 + 61660006001574.
It is an arithmetic number, because the mean of its divisors is an integer number (61660006001574).
Almost surely, 2123320012003147 is an apocalyptic number.
123320012003147 is a deficient number, since it is larger than the sum of its proper divisors (1).
123320012003147 is an equidigital number, since it uses as much as digits as its factorization.
123320012003147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 29.
Adding to 123320012003147 its reverse (741300210023321), we get a palindrome (864620222026468).
The spelling of 123320012003147 in words is "one hundred twenty-three trillion, three hundred twenty billion, twelve million, three thousand, one hundred forty-seven".
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