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1233202112113 is a prime number
BaseRepresentation
bin10001111100100000100…
…100101110011001110001
311100220002222100011101111
4101330200210232121301
5130201044220041423
62342305241033321
7155044616666506
oct21744044563161
94326088304344
101233202112113
11435aa8496374
1217b004a85841
138c3a11aaaaa
1443989d4b4ad
15221299cd60d
hex11f2092e671

1233202112113 has 2 divisors, whose sum is σ = 1233202112114. Its totient is φ = 1233202112112.

The previous prime is 1233202112071. The next prime is 1233202112147. The reversal of 1233202112113 is 3112112023321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 857889045729 + 375313066384 = 926223^2 + 612628^2 .

It is a cyclic number.

It is not a de Polignac number, because 1233202112113 - 221 = 1233200014961 is a prime.

It is not a weakly prime, because it can be changed into another prime (1233202112173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 616601056056 + 616601056057.

It is an arithmetic number, because the mean of its divisors is an integer number (616601056057).

Almost surely, 21233202112113 is an apocalyptic number.

It is an amenable number.

1233202112113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1233202112113 is an equidigital number, since it uses as much as digits as its factorization.

1233202112113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 1233202112113 its reverse (3112112023321), we get a palindrome (4345314135434).

The spelling of 1233202112113 in words is "one trillion, two hundred thirty-three billion, two hundred two million, one hundred twelve thousand, one hundred thirteen".