Base | Representation |
---|---|
bin | 11100000010100011110100… |
… | …100001000100000111000011 |
3 | 121011122101120200202010211002 |
4 | 130002203310201010013003 |
5 | 112130443311021423133 |
6 | 1114140551222042215 |
7 | 34655443244426153 |
oct | 3402436441040703 |
9 | 534571520663732 |
10 | 123321203311043 |
11 | 36326257323641 |
12 | 119b858557936b |
13 | 53a71a784666a |
14 | 2264ac7102763 |
15 | e3cd02c65ce8 |
hex | 7028f48441c3 |
123321203311043 has 2 divisors, whose sum is σ = 123321203311044. Its totient is φ = 123321203311042.
The previous prime is 123321203311021. The next prime is 123321203311049. The reversal of 123321203311043 is 340113302123321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 123321203311043 - 212 = 123321203306947 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 123321203310997 and 123321203311015.
It is not a weakly prime, because it can be changed into another prime (123321203311049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61660601655521 + 61660601655522.
It is an arithmetic number, because the mean of its divisors is an integer number (61660601655522).
Almost surely, 2123321203311043 is an apocalyptic number.
123321203311043 is a deficient number, since it is larger than the sum of its proper divisors (1).
123321203311043 is an equidigital number, since it uses as much as digits as its factorization.
123321203311043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7776, while the sum is 29.
Adding to 123321203311043 its reverse (340113302123321), we get a palindrome (463434505434364).
The spelling of 123321203311043 in words is "one hundred twenty-three trillion, three hundred twenty-one billion, two hundred three million, three hundred eleven thousand, forty-three".
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