Base | Representation |
---|---|
bin | 10001111100100001101… |
… | …110011101011011010001 |
3 | 11100220011022201011221211 |
4 | 101330201232131123101 |
5 | 130201114142104413 |
6 | 2342311211220121 |
7 | 155045243202565 |
oct | 21744156353321 |
9 | 4326138634854 |
10 | 1233221441233 |
11 | 436008398651 |
12 | 17b00b447641 |
13 | 8c3a51b7a42 |
14 | 4398c73d6a5 |
15 | 2212b54a83d |
hex | 11f21b9d6d1 |
1233221441233 has 2 divisors, whose sum is σ = 1233221441234. Its totient is φ = 1233221441232.
The previous prime is 1233221441209. The next prime is 1233221441261. The reversal of 1233221441233 is 3321441223321.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1141720031169 + 91501410064 = 1068513^2 + 302492^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1233221441233 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1233221441195 and 1233221441204.
It is not a weakly prime, because it can be changed into another prime (1233221141233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 616610720616 + 616610720617.
It is an arithmetic number, because the mean of its divisors is an integer number (616610720617).
Almost surely, 21233221441233 is an apocalyptic number.
It is an amenable number.
1233221441233 is a deficient number, since it is larger than the sum of its proper divisors (1).
1233221441233 is an equidigital number, since it uses as much as digits as its factorization.
1233221441233 is an evil number, because the sum of its binary digits is even.
The product of its digits is 20736, while the sum is 31.
Adding to 1233221441233 its reverse (3321441223321), we get a palindrome (4554662664554).
The spelling of 1233221441233 in words is "one trillion, two hundred thirty-three billion, two hundred twenty-one million, four hundred forty-one thousand, two hundred thirty-three".
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