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12332323433 is a prime number
BaseRepresentation
bin10110111110001000…
…00101001001101001
31011211110102221101202
423133010011021221
5200224033322213
65355420253545
7614415006503
oct133704051151
934743387352
1012332323433
115259303141
1224820a12b5
131216c6c001
1484dc06d73
154c2a16b58
hex2df105269

12332323433 has 2 divisors, whose sum is σ = 12332323434. Its totient is φ = 12332323432.

The previous prime is 12332323397. The next prime is 12332323463. The reversal of 12332323433 is 33432323321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9975415129 + 2356908304 = 99877^2 + 48548^2 .

It is a cyclic number.

It is not a de Polignac number, because 12332323433 - 28 = 12332323177 is a prime.

It is a super-2 number, since 2×123323234332 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12332323396 and 12332323405.

It is not a weakly prime, because it can be changed into another prime (12332323463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6166161716 + 6166161717.

It is an arithmetic number, because the mean of its divisors is an integer number (6166161717).

Almost surely, 212332323433 is an apocalyptic number.

It is an amenable number.

12332323433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12332323433 is an equidigital number, since it uses as much as digits as its factorization.

12332323433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 23328, while the sum is 29.

Adding to 12332323433 its reverse (33432323321), we get a palindrome (45764646754).

The spelling of 12332323433 in words is "twelve billion, three hundred thirty-two million, three hundred twenty-three thousand, four hundred thirty-three".