Base | Representation |
---|---|
bin | 1011001101111000000000… |
… | …1010000010000010000011 |
3 | 1121200000122001121211002101 |
4 | 2303132000022002002003 |
5 | 3104030441303021402 |
6 | 42121411425531231 |
7 | 2412013160461042 |
oct | 263360012020203 |
9 | 47600561554071 |
10 | 12333001220227 |
11 | 3a2543a739326 |
12 | 14722751a3b17 |
13 | 6b5cc660432c |
14 | 308cc59ac559 |
15 | 165c2293db87 |
hex | b3780282083 |
12333001220227 has 2 divisors, whose sum is σ = 12333001220228. Its totient is φ = 12333001220226.
The previous prime is 12333001220203. The next prime is 12333001220231. The reversal of 12333001220227 is 72202210033321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12333001220227 - 227 = 12332867002499 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12333001220195 and 12333001220204.
It is not a weakly prime, because it can be changed into another prime (12333001220927) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6166500610113 + 6166500610114.
It is an arithmetic number, because the mean of its divisors is an integer number (6166500610114).
Almost surely, 212333001220227 is an apocalyptic number.
12333001220227 is a deficient number, since it is larger than the sum of its proper divisors (1).
12333001220227 is an equidigital number, since it uses as much as digits as its factorization.
12333001220227 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 28.
Adding to 12333001220227 its reverse (72202210033321), we get a palindrome (84535211253548).
The spelling of 12333001220227 in words is "twelve trillion, three hundred thirty-three billion, one million, two hundred twenty thousand, two hundred twenty-seven".
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